La correction d'Exercice sur le calcul des tentions et de potentiels 3 (Loi des mailles)

Retour à l'exercice

On donne U_AB = 8V, U_BD = 10V, U_ED = -6V,  U_BC = 6V  et U_DF = 2V  

1)    U_CD = U_C - U_D = (U_C – U_B) + (U_B - U_D) = - U_BC +U_BD  = - 6V + 10V = 4V
U_EF = U_E – U_F = (U_E – U_D) + (U_D – U_D) = U_ED + U_DF = - 6V + 2V = -4V
U_AE = U_A – U_E = (U_A – U_B) + (U_B – U_D) + (U_D – U_E) = U_AE + U_BD + U_DE = 8V + 10V + 6V= 24V

2)   Si  U_E = 0,   U_AE = U_A – U_E = U_A – 0V = 24V   ⇒   U_A = 24V   U_AB = U_A – U_B= 24V - U_B = 8V   ⇒   U_B = 24V - 8V = 16V U_BC = U_B – U_C = 16V - U_C = 6V   ⇒   U_C = 16V – 6V = 10V U_ED = U_E – U_D = 0V - U_D = -6V  ⇒   U_D = 0V – (-6V) = 6V U_DF = U_D – U_F = 6V - U_F = 2V  ⇒   U_F = 6V - 2V = 4V 

Retour à l'exercice

retour à la liste des exercice des Circuits électriques